(4x^3-6x^2+2x)/(6y^2+2y-5y^4)=0

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Solution for (4x^3-6x^2+2x)/(6y^2+2y-5y^4)=0 equation: 


D( x )

6*y^2-(5*y^4)+2*y = 0

6*y^2-(5*y^4)+2*y = 0

6*y^2-(5*y^4)+2*y = 0

6*y^2-5*y^4+2*y = 0

6*y^2-5*y^4+2*y = 0

x naleu017Cy do R

x belongs to the empty set

(4*x^3-(6*x^2)+2*x)/(6*y^2-(5*y^4)+2*y) = 0

x belongs to the empty set

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